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🔢 Quant

Modern Maths

Permutation & Combination, Probability, Set Theory, Progressions. Usually 3–5 questions.

5%
of Quant

Why This Topic Matters

Total PYQs📊
17
of 1002 · 2021–2025
Years featured📅
5/5
of recent CAT years
% of Quant📈
~5%
of section questions
Est. hours⏱️
~8h
to master
1/22
2021
~2/22
2022
~1/22
2023
~2/22
2024
~2/22
2025

Few questions, high yield

Modern Maths — Permutations & Combinations, Probability, and Set Theory — is roughly 1 of the 22 Quant questions per slot. The concepts are small in number and reusable, so the return on mastering them is high. Each area has its own page; here are the load-bearing ideas.

What CAT 2021–2025 actually asked

Sub-skill20212022202320242025Avg/slot
Permutation & Combination1.01.00.31.01.00.9
Set theory (often with statistics)0.30.30.30.2
Probability0.30.1
🎯PYQ Evidence

Budget by the data: P&C first, the rest second. Counting questions appeared every year (13 of the 17 Modern Math questions). Pure probability appeared exactly once in five years (2024) — and even that one leaned on counting. Set theory surfaced three times, usually fused with averages/statistics. If you have limited hours, drill P&C deeply and treat probability as "P&C divided by a total," which is genuinely what CAT makes it.

Counting — permutations vs combinations

  • Fundamental rule: if a task splits into stages with mm and nn choices, the total is m×nm\times n (AND ⇒ multiply); mutually exclusive cases add (OR ⇒ add).
  • Order matters → permutations: nPr=n!(nr)!^nP_r=\dfrac{n!}{(n-r)!}.
  • Order doesn't matter → combinations: nCr=n!r!(nr)!^nC_r=\dfrac{n!}{r!\,(n-r)!}, with the symmetry nCr=nCnr^nC_r={}^nC_{\,n-r}.
⚠️CAT Trap

The order-matters slip. The single most common Modern Math error is using a permutation where a combination is meant (or vice-versa). Ask: would swapping two chosen items create a genuinely different outcome? If no, it's a combination. Two siblings of this trap that CAT loves: seating around a circle divides a row count by the rotations (n!(n1)!n! \to (n-1)!), and identical objects divide by the repeats (n!a!b!\frac{n!}{a!\,b!}). Both appeared in recent papers' counting questions — the wrong option is always the un-divided count.

Probability — and the complement trick

Basic probability is favourabletotal\dfrac{\text{favourable}}{\text{total}}, but on CAT the fast route is often the complement:

P(at least one)=1P(none)P(\text{at least one})=1-P(\text{none})

Build a probability tree when events happen in stages: multiply along a path (AND), add across disjoint paths (OR), and the branches at any node sum to 1. Conditional probability is

P(AB)=P(AB)P(B).P(A\mid B)=\frac{P(A\cap B)}{P(B)}.

Set theory — the inclusion–exclusion formulas

Two sets:   AB=A+BAB\;|A\cup B|=|A|+|B|-|A\cap B|.

Three sets:

ABC=A+B+CABBCCA+ABC|A\cup B\cup C|=|A|+|B|+|C|-|A\cap B|-|B\cap C|-|C\cap A|+|A\cap B\cap C|

A Venn diagram with the innermost region filled first (working outward) handles almost every CAT set question.

A worked example

✏️Worked Example

A bag holds 4 red and 6 blue balls. Two are drawn at random. What is the probability of at least one red?

Go through the complement — "no red" means both blue:

P(both blue)=610×59=3090=13.P(\text{both blue})=\frac{6}{10}\times\frac{5}{9}=\frac{30}{90}=\frac13.

P(at least one red)=113=23.P(\text{at least one red})=1-\frac13=\boxed{\dfrac23}.

Counting the "at least one" cases directly would mean adding exactly one red and both red — the complement does it in one line.

Where to go deeper

Dedicated pages: Permutations & Combinations, Probability, Set Theory (and Sequences & Series, housed under Algebra).

🎯PYQ Evidence
Counting problems split into three moves: multiply independent choices, subtract bad cases, or squeeze an overlap. : the mandatory picks multiply (5×4×2 = 40) while the optional sauces (0, 1, or 2 of 6) are counted as C(6,0)+C(6,1)+C(6,2) = 22 and added, giving 880. : count all 3⁶ functions, then inclusion-exclusion subtracts those missing a target — C(3,1)·2⁶ back to C(3,2)·1⁶ — leaving 540 surjections. : the all-three count is squeezed between the smallest single group (52) above and the totals-minus-class-size forced minimum below, and the gap is the answer. Ask whether the choices are independent, whether to remove forbidden cases, or whether you're bounding an overlap.

Checklist

  • Decide permutation vs combination by asking if order matters
  • Circle seating → (n1)!(n-1)!; identical objects → divide by repeats
  • Reach for 1P(none)1-P(\text{none}) on "at least one" questions
  • Multiply along a tree path (AND), add across paths (OR)
  • Fill the innermost Venn region first
  • Keep the 3-set inclusion–exclusion formula at your fingertips

Sample Questions

36 practice questions

TITAMedium

How many distinct arrangements can be formed using all the letters of the word MISSISSIPPI?

Your answer
Easy

In how many ways can 7 distinct people be seated around a circular table?

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CAT PYQ Spotlight

Actual CAT questions on this topic

CAT 2025 · Slot 1
TITAMedium

The number of distinct pairs of integers (x, y) satisfying the inequalities x > y ≥ 3 and x + y < 14 is

Your answer
CAT 2024 · Slot 1
TITAHard

The sum of all four-digit numbers that can be formed with the distinct non-zero digits a, b, c, and d, with each digit appearing exactly once in every number, is 153310 + n, where n is a single digit natural number. Then, the value of (a + b + c + d + n) is

Your answer

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