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🔢 Quant

Triangles

Properties, similarity, congruence, and area of triangles.

4%
of Quant

Why This Topic Matters

Total PYQs📊
14
of 1002 · 2021–2025
Years featured📅
5/5
of recent CAT years
% of Quant📈
~4%
of section questions
Est. hours⏱️
~10h
to master
~1/22
2021
~2/22
2022
~1/22
2023
1/22
2024
1/22
2025
🎯PYQ Evidence

CAT 2021–2025: ~0.9 per slot (2021: 0.7 · 2022: 1.3 · 2023: 0.7 · 2024: 1.0 · 2025: 1.0). Every year; similarity and right-triangle configurations dominate.

Triangles

The single richest figure in CAT geometry. A handful of results — angle sum, area, Pythagoras, and similarity — cover the great majority of questions.

Essentials

  • Angle sum =180°=180°; the exterior angle equals the sum of the two remote interior angles.
  • Area =12bh=\dfrac12\,b\,h, or Heron's s(sa)(sb)(sc)\sqrt{s(s-a)(s-b)(s-c)} with s=a+b+c2s=\dfrac{a+b+c}{2}.
  • Pythagoras a2+b2=c2a^2+b^2=c^2; recognise the triples 3-4-5, 5-12-13, 8-15-17.
  • Similarity (AA): equal angles ⇒ proportional sides, and areas scale as the square of the side ratio.
  • Centroid divides each median in a 2:12{:}1 ratio; inradius r=Areasr=\dfrac{\text{Area}}{s}; circumradius R=abc4AreaR=\dfrac{abc}{4\,\text{Area}}.

A worked example

Find the area of a triangle with sides 13, 14, 15.

14 13 15

Semi-perimeter s=13+14+152=21s=\dfrac{13+14+15}{2}=21. Then

Area=21(2113)(2114)(2115)=21876=7056=84.\text{Area}=\sqrt{21\,(21-13)(21-14)(21-15)}=\sqrt{21\cdot8\cdot7\cdot6}=\sqrt{7056}=\mathbf{84}.

(With area 84 you can also get the inradius r=84/21=4r=84/21=4 and circumradius R=131415484=8.125R=\frac{13\cdot14\cdot15}{4\cdot84}=8.125.)

🎯PYQ Evidence
Convert area conditions into base or altitude relations before reaching for trig. : the three triangles share the same height onto BC, so their areas are proportional to the bases BP, BQ, BC — the AP and "1.5×" conditions become base conditions and PQ falls out directly. : drop the rectangle onto axes, get sides 45, 28, 53, spot the right angle, then apply the right-triangle inradius r = (leg1 + leg2 − hypotenuse)/2 = (45 + 28 − 53)/2 = 10. : in the isosceles triangle the altitude to the base is √(50²−40²) = 30, fixing the area, and every other altitude is just 2·area/side. The recurring trick: same height means area ∝ base, so each altitude is 2·area÷its side.

Common traps

  • Triangle inequality. Any side must be less than the sum of the other two — some "triangles" can't exist.
  • Similar ≠ congruent. Similar triangles share shape, not size; areas go as the square of the ratio.
  • Wrong height. The height must be perpendicular to the chosen base.

Checklist

  • Use Heron when you know all three sides
  • Spot Pythagorean triples to skip arithmetic
  • Apply area ratio = (side ratio)² for similar triangles
  • Recall centroid 2:1, r=Area/sr=\text{Area}/s, R=abc/4AreaR=abc/4\text{Area}

Sample Questions

18 practice questions

Medium

A figure is comprised of three squares and a triangle T. If the areas of the three squares are 25, 144, and 169, what is the area of triangle T?

Hard

In a triangle, if BE is parallel to CD and BC = AB = 3, AE = 4, CD = 10, what is the area of trapezoid BEDC?

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CAT PYQ Spotlight

Actual CAT questions on this topic

CAT 2025 · Slot 2
Hard

In a △ABC, points D and E are on the sides BC and AC, respectively. BE and AD intersect at point T such that AD : AT = 4 : 3, and BE : BT = 5 : 4. Point F lies on AC such that DF is parallel to BE. Then, BD : CD is

CAT 2024 · Slot 1
TITAMedium

ABCD is a rectangle with sides AB = 56 cm and BC = 45 cm, and E is the midpoint of side CD. Then, the length, in cm, of radius of incircle of △ADE is

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