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Integers, Factors & Remainders

Primes, prime factorization, divisibility tests, remainders, parity and digit logic — the number-property toolkit Quant leans on.

~5h
to master

What the GMAT does with integers

Integer questions on the GMAT are never "recite the definition" — they hand you a property (divisibility, parity, a remainder) and ask you to use it: simplify, count, or pin down an unknown. Master three machines: prime factorization, the remainder identity, and parity rules.

Core rules

📐Core Rule

Divisibility lives in prime factorizations. Integer aa divides integer bb exactly when every prime in aa's factorization appears in bb's at least as high a power. 2376=2333112376 = 2^3 \cdot 3^3 \cdot 11 is divisible by 24=23324 = 2^3 \cdot 3, but not by 16=2416 = 2^4 (not enough 2s) and not by 21=3721 = 3 \cdot 7 (no 7 at all).

  • Primes: exactly two positive divisors. 22 is the only even prime; 11 is not prime.
  • The remainder identity: dividing nn by dd gives unique q,rq, r with n=dq+rn = dq + r and 0r<d0 \le r < d. When the dividend is smaller than the divisor, the quotient is 00 and the whole dividend carries over as the remainder.
  • Remainders respect + and ×: the remainder of a sum (or product) equals the remainder of the sum (or product) of the remainders. To find (143+31)mod13(143 + 31) \bmod 13: 1430143 \to 0, 31531 \to 5, so the answer is 55 — no big addition needed.
  • Parity: a product is even if any factor is even; a sum of two integers is even exactly when the two have the same parity. Consecutive integers always contain a multiple of 2, of 3 (among any three), and so on.

Divisibility tests (memorize cold): by 2 — last digit even · by 3 — digit sum divisible by 3 · by 4 — last two digits · by 5 — ends in 0/5 · by 9 — digit sum · by 10 — ends in 0.

✏️Worked Example

How many three-digit multiples of 7 are there? Smallest: 105=715105 = 7 \cdot 15. Largest: 994=7142994 = 7 \cdot 142. Count =14215+1=128= 142 - 15 + 1 = 128. The +1+1 is the classic fence-post step — count posts, not gaps.

Last-digit arithmetic

The final digit of a sum or product depends only on the final digits of the inputs. The last digit of 345×789345 \times 789 is the last digit of 5×9=455 \times 9 = 45, i.e. 55. Powers cycle: 71,72,73,747^1, 7^2, 7^3, 7^4 end in 7,9,3,17, 9, 3, 1 and then repeat with period 4 — so the units digit of 7507^{50} is the digit at position 50mod4=250 \bmod 4 = 2 in the cycle: 99.

Digits as algebra

A two-digit number with tens digit tt and units digit uu is 10t+u10t + u; its reversal is 10u+t10u + t. Their difference is 9(tu)9(t - u) — always a multiple of 9. Place-value translation turns digit puzzles into one-line algebra. Try it inline: .
⚠️GMAT Trap

"Divisible by 6 and 4" does not mean divisible by 24. Combine conditions with the LCM, not the product: lcm(6,4)=12\text{lcm}(6,4) = 12 (their prime demands overlap in a 2). The product rule only works when the divisors are coprime.

💡Exam Tip
When a question says "nn leaves remainder 3 when divided by 7", immediately write n=7k+3n = 7k + 3 and work with that expression. Concrete test values (3,10,173, 10, 17) are the fastest way to kill wrong options. Practice the move on .

Checklist

  • Factor into primes before reasoning about divisibility
  • Translate remainder statements into n=dq+rn = dq + r form
  • Use parity to eliminate options before computing
  • Digit puzzles → place-value algebra (10t+u10t + u)
  • Count inclusive ranges with the +1+1

Sample Questions

22 practice questions

Medium

When the positive integer nn is divided by 9, the remainder is 5. What is the remainder when 3n+83n + 8 is divided by 9?

Medium

When the digits of a two-digit positive integer are reversed, the resulting integer is 36 greater than the original integer. What is the positive difference between the two digits?

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