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Statistics & Averages

Mean via sums, medians by position, weighted averages, frequency tables, and what standard deviation responds to.

~5h
to master

The five measures, and what each one ignores

MeasureDefinitionBlind spot
Meansum ÷ countdistorted by outliers
Medianmiddle of the sorted list (average of the middle two if count is even)ignores how far values sit
Modemost frequent value (can be several)ignores everything else
Rangemax − minuses only two values
Standard deviationtypical distance from the meanhardest to compute — GMAT asks for comparisons, not decimals

Repeated values count every time they appear: the mean of 6,4,7,10,46, 4, 7, 10, 4 is 315=6.2\frac{31}{5} = 6.2, with both 4s in the sum.

Work with the sum, not the mean

📐Core Rule

sum=mean×count\text{sum} = \text{mean} \times \text{count} — the most useful identity in the topic. Four people average 80 miles → total 320; three drove 72+78+83=23372 + 78 + 83 = 233 → the fourth drove 8787. Every "find the missing value" question is this one move.

The same identity powers average-shift problems: if nn days average 50 units and today's 90 units lifts the average to 55, then old sum +90=+ 90 = new sum: 50n+90=55(n+1)50n + 90 = 55(n + 1)n=7n = 7. Practice it on .
  • Weighted average: with group sizes n1,n2n_1, n_2 and means m1,m2m_1, m_2, the overall mean is n1m1+n2m2n1+n2\frac{n_1 m_1 + n_2 m_2}{n_1 + n_2} — it lands between the group means, closer to the larger group. It never equals the simple midpoint unless the groups match in size.

Median: position, not value

Sort first — always. For the five daily ticket counts 7,4,9,4,67, 4, 9, 4, 6, the sorted list 4,4,6,7,94,4,6,7,9 has median 6. With an even count, average the two middle entries. The median can equal, exceed, or trail the mean; skewed data drags the mean toward the tail while the median barely moves. "About half the values are below the median" is usually true but fails with heavy ties — a list can have most values equal to its median.

Mean vs median questions ("for which value are they equal?") are case checks: for each candidate, recompute both — the mean moves smoothly with the new value, the median only jumps when the order changes. See .

Evenly spaced lists

For consecutive integers — or any arithmetic sequence — mean == median == the midpoint of first and last. Sliding a whole list up by kk slides its mean by exactly kk; the spread (range, SD) doesn't move. Ten consecutive odd integers starting 7 above another list's start have a mean exactly... well, that's a one-line deduction once you trust the midpoint rule.

Standard deviation, conceptually

  1. Find the mean. 2. Square each deviation from it. 3. Average the squares. 4. Square-root.

What the GMAT actually tests:

  • Tighter clustering = smaller SD — compare {6,6,6.5,7.5,9}\{6, 6, 6.5, 7.5, 9\} vs {0,7,8,10,10}\{0, 7, 8, 10, 10\} (same mean 7; the first is far tighter).
  • Adding a constant to every value: SD unchanged. Multiplying every value by kk: SD scales by k|k|.
  • Adding values at the mean shrinks SD; adding values far from the mean grows it.
  • SD =0= 0 exactly when all values are equal.
⚠️GMAT Trap

Range and SD are different animals. Two sets can share a range while one has nearly all its weight at the endpoints (big SD) and the other clusters at the centre (small SD). Never infer SD from range — or from the mean.

💡Exam Tip

Frequency tables are compressed lists. A value with frequency 7 appears 7 times in mean and median bookkeeping. For the median, find which value spans the middle position (n+12\frac{n+1}{2} for odd nn) by accumulating frequencies.

Checklist

  • Mean questions → convert to sums immediately
  • Sort before taking any median
  • Weighted mean leans toward the bigger group
  • Evenly spaced → mean = median = midpoint
  • SD: shift-invariant, scale-by-k|k|, clustering beats range

Sample Questions

22 practice questions

Medium

Over her first nn games of a season, a bowler averaged 140 points per game. After scoring 188 points in her next game, her average for the season rose to 146 points per game. What is the value of nn?

Hard

The five numbers 4, 9, 10, 13, and xx have an average (arithmetic mean) equal to their median. Which of the following could be the value of xx?

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