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🔢 Quant

Sequences & Series

Arithmetic, geometric and special series.

7%
of Quant

Why This Topic Matters

Total PYQs📊
22
of 1002 · 2021–2025
Years featured📅
5/5
of recent CAT years
% of Quant📈
~7%
of section questions
Est. hours⏱️
~8h
to master
~2/22
2021
~2/22
2022
2/22
2023
~2/22
2024
~2/22
2025
🎯PYQ Evidence

CAT 2021–2025: ~1.5 per slot (2021: 1.3 · 2022: 1.3 · 2023: 2.0 · 2024: 1.3 · 2025: 1.3). Progressions appeared every year (1–2 per slot) — AP/GP sums, common terms of two APs, and telescoping are the staples.

Sequences & Series

CAT favours the two classic progressions — arithmetic (constant difference) and geometric (constant ratio) — plus a few special sums.

Arithmetic progression (AP)

nn-th term   tn=a+(n1)d  \;t_n=a+(n-1)d\; and sum

Sn=n2[2a+(n1)d]=n2(first+last).S_n=\frac n2\big[\,2a+(n-1)d\,\big]=\frac n2\,(\text{first}+\text{last}).

Geometric progression (GP)

nn-th term   tn=arn1  \;t_n=a\,r^{\,n-1}\; and sum

Sn=arn1r1 (r1);S=a1r for r<1.S_n=a\,\frac{r^n-1}{r-1}\ (r\ne1);\qquad S_\infty=\frac{a}{1-r}\ \text{for}\ |r|<1.

A worked example

Find the sum of the first 20 terms of 3,7,11,15,3,\,7,\,11,\,15,\dots

This is an AP with a=3a=3, d=4d=4, n=20n=20:

S20=202[2(3)+19(4)]=10(6+76)=1082=820.S_{20}=\frac{20}{2}\big[\,2(3)+19(4)\,\big]=10\,(6+76)=10\cdot82=\mathbf{820}.

Special sums worth memorising

k=1nk=n(n+1)2,k2=n(n+1)(2n+1)6,k3=(n(n+1)2)2.\sum_{k=1}^{n}k=\frac{n(n+1)}2,\quad \sum k^2=\frac{n(n+1)(2n+1)}6,\quad \sum k^3=\left(\frac{n(n+1)}2\right)^2.

🎯PYQ Evidence
Find the hidden structure — a block, a difference of sums, or a clean doubling. : the value of floor(√n) stays constant between consecutive perfect squares, with exactly 2k+1 values of n giving k, so you add a handful of blocks instead of 50 terms and reach 217. : recover the nth term as a_n = S_n − S_{n−1} = 4n − 1, then "divisible by 9" is just a remainder condition mod 9, giving the smallest n = 7. : the messy rule a_n = 2a_{n−1} + 3 becomes exact doubling once you add 3 — a_n + 3 = 2(a_{n−1} + 3) — so a_n + 3 = 5·2^(n−1), and crossing one million needs n = 19. Reshape the sequence into something that adds or doubles cleanly and the bound falls out.

Common traps

  • AP vs GP mix-up. Check whether terms differ by adding (AP) or multiplying (GP).
  • Counting terms. From term pp to term qq inclusive there are qp+1q-p+1 terms — off-by-one errors are common.
  • Infinite GP condition. SS_\infty exists only when r<1|r|<1.

Checklist

  • Identify AP (common difference) vs GP (common ratio)
  • Sn=n2(first+last)S_n=\frac n2(\text{first}+\text{last}) for any AP
  • Use a(rn1)r1\frac{a(r^n-1)}{r-1} for GP; a1r\frac{a}{1-r} for infinite
  • Keep the k, k2, k3\sum k,\ \sum k^2,\ \sum k^3 formulas ready

Sample Questions

31 practice questions

Easy

In an increasing sequence of 5 consecutive even integers, the sum of the second, third, and fourth integers is 132. What is the sum of the first and last integers in the sequence?

Easy

What is the sum of all the multiples of 7 from 84 to 140, inclusive?

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CAT PYQ Spotlight

Actual CAT questions on this topic

CAT 2025 · Slot 1
Medium

In the set of consecutive odd numbers {1, 3, 5, ……, 57}, there is a number of k such that the sum of all the elements less than k is equal to the sum of all the elements greater than k. Then, k equals.

CAT 2024 · Slot 1
TITAMedium

For any natural number n, let aₙ be the largest integer not exceeding n\sqrt{n}. Then the value of a₁ + a₂ + … + a₅₀ is

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